How to get a list of all pinged members in a message (not interaction)

5 Replies

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xoxo__cool_tabahi__xoxo•2y ago

const mentionedMember = <Message>.mentions.members.map(mem=> mem)

const mentionedMember = <Message>.mentions.members.map(mem=> mem)

mentionedMember is an array of the members also alternatively too loop through each member you can use

<Message>.mentions.members?.forEach((mem)=>{
        console.log(mem)
    })

<Message>.mentions.members?.forEach((mem)=>{
        console.log(mem)
    })

chewie•2y ago

Generelly message.mentions.members returns a collection of pinged members Turning it to an array is pointless most of the time

MyzOP•2y ago

Okay, thanks i was doing message.mentions.first() what are the exceptions

chewie•2y ago

I dont know any

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How to get a list of all pinged members in a message (not interaction)