Java Community | Help. Code. Learn.•3y ago

Object sequential searching using compareTo()

I have this simple method to search for an object that uses

Comparable

Comparable

interface. But I'm wondering, why does my parameter should use

extends

extends

instead of

implements

implements

? Doesn't this break the law where an object can only extend ONE class, but is able to implement multiple interfaces? So why doesn't

implements

implements

work here?

    public static <T extends Comparable<T>> int sequentialSearch(T[] list, T key) {
        for (int i = 0; i < list.length; i++) {
            if (list[i].compareTo(key) == 0)
                return i;
        }
        return -1;
    }

    public static <T extends Comparable<T>> int sequentialSearch(T[] list, T key) {
        for (int i = 0; i < list.length; i++) {
            if (list[i].compareTo(key) == 0)
                return i;
        }
        return -1;
    }

JavaBot•5/25/23, 3:16 AM

JavaBot•5/25/23, 3:17 AM

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circleOP•5/25/23, 3:18 AM

why isn't it:

circleOP•5/25/23, 3:37 AM

Another method I can use is using raw implementation of casting the to be compared object to

Comparable

Comparable

interface. But this still means it was casted to a class(?) instead of the interface.

JavaBot•5/25/23, 11:30 AM

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Ooppa @circle Interfaces do not implement other interfaces, they can tho be extended ...

circleOP•5/29/23, 6:50 AM

Sorry for the late reply, does that mean T as the parameter data type is already an interface?

circleOP•5/29/23, 6:52 AM

TIA

JavaBot•5/29/23, 12:10 PM

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Ooppa @circle no T may be any data type that implements the `Comparable` Interface E...

circleOP•5/31/23, 4:41 PM

So T can be extended into any interface? Even though interface is not a class?

Carter3&1/2•5/31/23, 5:05 PM

is valid syntax

JavaBot•5/31/23, 10:20 PM

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