use optional method in interface as type to array

i have this interface (notice how the methods are made optional)

interface Module {
    Start?(): void;
    CharacterAdded?(char: Model): void;
};

interface Module {
    Start?(): void;
    CharacterAdded?(char: Model): void;
};

i have this array

const characterAddedFuncs: Array<Module['CharacterAdded']> = [];

const characterAddedFuncs: Array<Module['CharacterAdded']> = [];

the problem with the type of the array is that it keeps the 'optional-ability' from the type of CharacterAdded. This is causing me problems elsewhere in the code. How can I essentially omit the optional part? The current type of 'characterAddedFuncs':

const characterAddedFuncs: (((char: Model) => void) | undefined)[]

const characterAddedFuncs: (((char: Model) => void) | undefined)[]

I want it to be

const characterAddedFuncs: ((char: Model) => void)[]

const characterAddedFuncs: ((char: Model) => void)[]

2 Replies

Fireboltofdeath•2y ago

NonNullable<Module["CharacterAdded"]>

CriShouxOP•2y ago

thank you that works

Gaming

Programming

use optional method in interface as type to array

Did you find this page helpful?