✅ 0-1 sine wave
Just a super general math question. If I want a sine wave which has a period of 1 and an amplitude of 1 which goes between 0 and 1, what would be the most concise way to write that? I.e.
f(0) = 0, f(0.5) = 1, f(1) = 0, as a sine wave.25 Replies
I can come up with
-((cos(2 * pi * x) - 1) / 2) but was just wondering if there some more elegant way to write it.Won't it be just 
?
sin(2 * pi * x) ?
y = sin(2 * pi * x) @🌈 Thinker 🌈isn't that just sin(πx)
it follows the examples you gave at least
well
black is
sin(2 * pi * x), red is the desired curveoh I'm stupid
I think red is just
sin(pi * x)
I thought you wanted entire period of wave to be within 0 to 1
half a period would be sin(pi * x)ah, my bad on terminology then
just 
abs(sin(pi * x))? bouncy
yeah, you're right
shows how much I got out of trig in high school
well when actual math fails me there's always the backup
what the hell is
sin²sin, squared
it's the same as
sin()²ah
huh
yeah that works, now I'm just why
why that works or how it got to that
nvm
for the second, this
you have Wolfram Alhpa pro?
nope! the mobile app just acts like you do, no idea why
best 3 usd I've ever spent
is it just me or is the shown solution here not exactly what was asked.. i just tried it and it starts at 1 instead of 0
which you then also could just do:
sin²(πx) starts at 0
uuuh crap my bad
-cos(2 * pi * x) / 2 + 0.5jea i missed the - -.-