✅ Initializing 'double's maximum value; Exeption
Hello hello (: ... silly little question!
Went over to C#-doc and looked up built-in data types and, for funsies, CTRL-C/V them all down and initialized em' with their biggest value. All dandy, but not for the dreaded 'double'! It threw an error. Floating-point constant is outside the range of type 'double'.
Asked ChatGPT and tried finding something on the internet, and the answer was:
The reason you can't initialize a double with the value of 1.79769313486232e308 is because this is the maximum value that a double can represent in C#.
Which i dont truly understand! If it is the maximum-value, why cant i assign it? It works with all the other built-in data types. ):
https://media.discordapp.net/attachments/1068421165086937108/1080521899760685146/image.png?width=539&height=60
https://media.discordapp.net/attachments/1068421165086937108/1080522173816524881/image.png?width=580&height=292
5 Replies
use double.MaxValue
according to https://learn.microsoft.com/en-us/cpp/c-language/type-float?view=msvc-170 it's 1.7976931348623158 E + 308
Type float
Learn more about: Type float
not 232E
Oh heck! Thanks ... the course provided a link to the documentation, from where i grabbed that number (first screenshot) 🤔 maybe that was the wrong doc. I've no idea why they linked that
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/close - otherwise I will mark this as stale and this post will be archived until there is new activity.