Theo's Typesafe Cult•2y ago

Can I zod this gamestate?

export interface GameState {
  id: string;
  status: "initializing" | "waitingOpponent" | "started" | "finished";
  field: Field;
  entities: Entity[];
  initiative: number[];
  round: number;
  turn: number;
  hands: Card[][];
  decks: Deck[];
}

export interface GameState {
  id: string;
  status: "initializing" | "waitingOpponent" | "started" | "finished";
  field: Field;
  entities: Entity[];
  initiative: number[];
  round: number;
  turn: number;
  hands: Card[][];
  decks: Deck[];
}

It's a game. There is more nested interfaces (Field, Entity, Card, Deck). Should I just give up and use z.any() or is this still reasonable with zod? 😄

4 Replies

CaptainStarz•2y ago

If you can write interfaces, you surely can write as many zod schemas poohheh

cyremurOP•2y ago

fine. meme question, I'll get around to it eventually was just hoping some zod wizards would show me the way to do this easier

CaptainStarz•2y ago

You can write schemas and infer types from them

Sean Cassiere•2y ago

const GameSchema = z.object({
  id: z.string(),
  status: z.enum("initializing","waitingOpponent","started","finished"),
  field: // your zod schema for this,
  entities: z.array(/** you zod schema for this */),
  initiative: z.array(z.number()),
  round: z.number(),
  turn: z.number(),
  hands: z.array(z.array(/** you zod schema for this */)),
  decks: z.array(/** you zod schema for this */)
});

export type TGameSchema = z.infer<typeof GameSchema>

const GameSchema = z.object({
  id: z.string(),
  status: z.enum("initializing","waitingOpponent","started","finished"),
  field: // your zod schema for this,
  entities: z.array(/** you zod schema for this */),
  initiative: z.array(z.number()),
  round: z.number(),
  turn: z.number(),
  hands: z.array(z.array(/** you zod schema for this */)),
  decks: z.array(/** you zod schema for this */)
});

export type TGameSchema = z.infer<typeof GameSchema>

Gaming

Programming

Can I zod this gamestate?