Kevin Powell - Community•2y ago

Clicking on one element sets it a class, while removing classes from other elements, dynamically.

This, I'm guessing, simple problem is giving me a headache for 3rd straight project in a row. If I for example have 6 buttons of the same class, and I click on any of them, that one gets class of "active". However, if I click on different button, any other button that has that "active" class should lose it. Or simplified, one 1 button can be "active" at the time. How do I achieve this dynamically, through loop, without having to add every button separately, and adding the same exact code to each with .add/.remove class that I have been doing until now?

21 Replies

13eck•2y ago

#How To Ask Good Questions . What have you tried? What code do you have?

Dovah•2y ago

Ohhhhhh you are here. Was looking for you few days ago. xD I have no code. xD Just add 6 buttons in HTML. That is it. 😄 And what I'm trying to do is when you click one of them for it to get its style changed so it looks active. But If I click any other, that one loses that style. We already had similar problem in the past with radio buttons. xD That you were helping me. Let me try and get code

for(let i=0;i<tipButton.length;i++) {
    tipButton[i].addEventListener('click', function(){
        tipButton[i].classList.toggle('active-button');
    })
}

for(let i=0;i<tipButton.length;i++) {
    tipButton[i].addEventListener('click', function(){
        tipButton[i].classList.toggle('active-button');
    })
}

This is the loop I would use

13eck•2y ago

Well, we won't spoon feed you the answer, but I can give you some tips: 1) On click, loop through all button elements you want and 1.1) Remove the active class on all of them 1.2) Add the active class to the clicked button You'll want to look into: • document.querySelectorAll() to get all the appropriate elements • for...of or forEach() loops to loop through the elements • classList.add() and classList.remove

Dovah•2y ago

tip button is just a class for all 6 buttons

13eck•2y ago

Oh, also, event delegation. Which is when you add an event listener on the parent element and do things to the children elements. This way you're only adding one event listener and if you add more elements later all will still be event-able

Dovah•2y ago

Yeah you were mentioning that last time. But the chat was not saved 😦 actually it was video call

13eck•2y ago

https://gomakethings.com/listening-for-events-on-multiple-elements-using-javascript-event-delegation/

Dovah•2y ago

Will you be able to do a video call any time in future? Or now if you are able?

13eck•2y ago

Basically:

<div class="tipJar">
  <button class="tip" data-tip="5">Tip 5%</button>
  <button class="tip" data-tip="10">Tip 10%</button>
  <button class="tip" data-tip="15">Tip 15%</button>
  <button class="tip" data-tip="25">Tip 25%</button>
</div>

<div class="tipJar">
  <button class="tip" data-tip="5">Tip 5%</button>
  <button class="tip" data-tip="10">Tip 10%</button>
  <button class="tip" data-tip="15">Tip 15%</button>
  <button class="tip" data-tip="25">Tip 25%</button>
</div>

document.querySelector(".tipJar").addEventListener("click", (ev) => {
  // ev.target is the element that was clicked on
  console.log(ev.target);
});

document.querySelector(".tipJar").addEventListener("click", (ev) => {
  // ev.target is the element that was clicked on
  console.log(ev.target);
});

Not for a while, no. Gonna be sitting down to lunch soon and then going to a movie with the wife

Dovah•2y ago

Roger. Let me see those pictures. 😄

13eck•2y ago

All that being said, why are you using buttons and no a radio input? Sounds like a perfect use case for it

Dovah•2y ago

Well I had the same problem with radio buttons And I'm just curious at this point. Let me try out this thingie you gave me. 😄 Can you say if not target somehow? wait

13eck•2y ago

You'll want to for...of loop through the tip buttons (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...of). It's better than the for loop you have above since it does the auto incrementing for you.

const tipJarBtns = document.querySelectorAll(".tipJar > button");
for (const btn of tipJarBtns) {
  //do stuff
}

const tipJarBtns = document.querySelectorAll(".tipJar > button");
for (const btn of tipJarBtns) {
  //do stuff
}

using my above for...of loop, you'd do something like:

if (btn !== ev.target) {
  // do something to the not-target of the click
}

if (btn !== ev.target) {
  // do something to the not-target of the click
}

Dovah•2y ago

Hmmmmmmmmm we are getting closer I think xD lemmie type it out How do you add ev.target into that

13eck•2y ago

You add that into the click handler, so the event is passed in

Dovah•2y ago

const tipJarBtns = document.querySelectorAll(".tipJar > button"); for (const btn of tipJarBtns) { //do stuff }

```js
const tipJarBtns = document.querySelectorAll(".tipJar > button");
for (const btn of tipJarBtns) {
  //do stuff
}

```js
const tipJarBtns = document.querySelectorAll(".tipJar > button");
for (const btn of tipJarBtns) {
  //do stuff
}

13eck•2y ago

Very basic example: https://codepen.io/c__beck/pen/poKBOVp

Christopher

CodePen

Event Delegation and loops

...

13eck•2y ago

Wife's home, lunch time. x13ladWave

Dovah•2y ago

Hmm I'm doing something wrong Have a nice meal! 😄 That is it! Finally Still need to learn that syntax ev => and so on target and so on Either way thanks a lot! LD 😄 But how do you remove class from the same button now? xD Buttons are perma active now, you can't turn them off.

13eck•2y ago

Just a small update to the codepen AND BOOM! Toggles the button if it's on to off

Dovah•2y ago

Niceeeeeeee! It works now! Thanks a lot! 😄

Gaming

Programming

Clicking on one element sets it a class, while removing classes from other elements, dynamically.