Everytime I move on to the next form my exit code activate for some reason [Answered]

I'm not sure I'm doing wrong
9 Replies
Buddy
Buddy3y ago
Use form124.Show(); instead of Application.Run form124 being the name of your variable of datatype Form. Application.Run should only be called once
Kaoruko Waguri
Kaoruko WaguriOP3y ago
@Buddy It's underlined
Kaoruko Waguri
Kaoruko WaguriOP3y ago
I'm on form2 rn
Buddy
Buddy3y ago
Form3 aaaa = new Form3();
aaaa.Show();
Form3 aaaa = new Form3();
aaaa.Show();
Kaoruko Waguri
Kaoruko WaguriOP3y ago
Oh
Kaoruko Waguri
Kaoruko WaguriOP3y ago
Buddy
Buddy3y ago
read the errors and follow them
Kaoruko Waguri
Kaoruko WaguriOP3y ago
@Buddy sorry for not following up with you but I fixed it thanks for the help
Accord
Accord3y ago
✅ This post has been marked as answered!
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