Kevin Powell - Community•2y ago

9 is higher than 871?

rowsDuplicate.sort((rowA, rowB) => {
        let cellA;
        let cellB;

        // Get the content of cells
        cellA = rowA.querySelectorAll('td')[1].innerHTML;
        cellB = rowB.querySelectorAll('td')[1].innerHTML;

        // descending order
        switch (true) {
            case cellA > cellB:
                return -1;
            case cellA < cellB:
                return 1;
            case cellA === cellB:
                return 0;
        }
    })

rowsDuplicate.sort((rowA, rowB) => {
        let cellA;
        let cellB;

        // Get the content of cells
        cellA = rowA.querySelectorAll('td')[1].innerHTML;
        cellB = rowB.querySelectorAll('td')[1].innerHTML;

        // descending order
        switch (true) {
            case cellA > cellB:
                return -1;
            case cellA < cellB:
                return 1;
            case cellA === cellB:
                return 0;
        }
    })

I have this sort, and for some reason 9 is greater than 871 for some reason. Is there a way to make it so that it reads the entire number not just the first digit?

2 Replies

13eck•2y ago

Sort of…but it's actually that "9" is greater than "871". Everything JS gets from HTML is a string, so it's comparing strings. If you Number([cell]) or parseInt([cell], 10) you'll get numbers and it will compare the way you expect.

kingtigerknight•2y ago

AHHHHH thanks. Forgot it's strings so I need to parse it.

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9 is higher than 871?