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C#•2y ago

out ref local?

Seems I am able to do this:

ref int Test1(){
    return ref ints[1];
}

ref int Test1(){
    return ref ints[1];
}

but not this:

void Test2(out ref int a){
    a = ref ints[1];
}

void Test2(out ref int a){
    a = ref ints[1];
}

is there some syntax im missing or is this just not possible?

9 Replies

dancepanda42•2y ago

you can only have one modifier.

Carsillas•2y ago

Yeah I realize that the syntax is illegal, im asking if this is possible some other way. Not sure why it would be allowed to return a ref but not out a ref I guess

dancepanda42•2y ago

for what at all? I could not think of any sensible reason for this.

Carsillas•2y ago

🧐 its no less sensible than returning a ref, do you see no reason for ever returning a ref? or specifically no sensible reason for outing one?

dancepanda42•2y ago

to declare a ref as out.

Carsillas•2y ago

Have you used ref locals before? I can't tell if you just dont understand the question or if you just think its a bad idea

dancepanda42•2y ago

i just think it's a bad idea.

ero•2y ago

out ref is being worked on And by worked on i mean it's in discussion

Carsillas•2y ago

Nice! was hoping someone else would comment haha, closing the topic now, thanks!

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