out ref local?
Seems I am able to do this:
but not this:
is there some syntax im missing or is this just not possible?
9 Replies
you can only have one modifier.
Yeah I realize that the syntax is illegal, im asking if this is possible some other way. Not sure why it would be allowed to return a ref but not out a ref I guess
for what at all?
I could not think of any sensible reason for this.
🧐 its no less sensible than returning a ref, do you see no reason for ever returning a ref? or specifically no sensible reason for outing one?
to declare a ref as out.
Have you used
ref locals before? I can't tell if you just dont understand the question or if you just think its a bad ideai just think it's a bad idea.
out ref is being worked on
And by worked on i mean it's in discussion
Nice! was hoping someone else would comment haha, closing the topic now, thanks!