How to type either

Quick question. I have an object I'm passing as a parameter. It has the shape
{id: number, name: string, foo: Partial<SomeObject>}
{id: number, name: string, foo: Partial<SomeObject>}
I need either or both id and name, and I require foo. How would I go about typing this?
5 Replies
Amos
Amos•3y ago
type SomeObject = Record<string, string>;

type OneOrTheOther =
| { id: number; foo: Partial<SomeObject> }
| { name: string; foo: Partial<SomeObject> }
| { id: number; name: string; foo: Partial<SomeObject> };

const MyThing: OneOrTheOther = { foo: {}, id: 1 };
type SomeObject = Record<string, string>;

type OneOrTheOther =
| { id: number; foo: Partial<SomeObject> }
| { name: string; foo: Partial<SomeObject> }
| { id: number; name: string; foo: Partial<SomeObject> };

const MyThing: OneOrTheOther = { foo: {}, id: 1 };
Does this work?
benten
bentenOP•3y ago
It does, idk why I didn't think of explicitly unioning the three possible versions thanks legend Hmm actually it's not It's telling me that id and name don't exist on type mything when i use it as a param hmm this works apparently
type TUpdateMeal =
| { id: number; name?: string; newState: Partial<TMeal> }
| { name: string; id?: number; newState: Partial<TMeal> }
type TUpdateMeal =
| { id: number; name?: string; newState: Partial<TMeal> }
| { name: string; id?: number; newState: Partial<TMeal> }
thanks for the help you got me 95% of the way there
Amos
Amos•3y ago
Can you do name?: never and id?: never to make it even more explicit (I had that before, but removed it since I thought it worked w/o 😓)
benten
bentenOP•3y ago
Would never imply it can't be two at once?
Amos
Amos•3y ago
Yeah you'd have to have the 3rd one saying it can be both
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