C#•3y ago

Combine two Expression Func [Answered]

I have two Expression<Func<A,A>>. I want to combine them into a single Expression<Func<A,A>> that runs the output of the first through the second. How can I do that?

13 Replies

Thinker•3y ago

Couldn't you create a new expression which is the equivalent of (x) => b(a(x))?

n8taOP•3y ago

I would like to combine the expressions programatically as opposed to writing the combo by hand. @thinker227

Thinker•3y ago

hold on

Anar•3y ago

Expression<Func<T, T>> chain = x => e2.Compile()(e1.Compile()(x));

Expression<Func<T, T>> chain = x => e2.Compile()(e1.Compile()(x));

Maaaybe this?

n8taOP•3y ago

Can't compile ahead of time that's done later in the process This eventually becomes SQL. Needs to stay as a proper expression.

Anar•3y ago

Never mind then.

Thinker•3y ago

This works

Expression<Func<int, int>> a = (int x) => x - 2;
Expression<Func<int, int>> b = (int x) => x * 2;

var param = Expression.Parameter(typeof(int), "x");
var c = Expression.Lambda<Func<int, int>>(Expression.Invoke(a, Expression.Invoke(b, param)), param);

var func = c.Compile();
int i = func(7);

Expression<Func<int, int>> a = (int x) => x - 2;
Expression<Func<int, int>> b = (int x) => x * 2;

var param = Expression.Parameter(typeof(int), "x");
var c = Expression.Lambda<Func<int, int>>(Expression.Invoke(a, Expression.Invoke(b, param)), param);

var func = c.Compile();
int i = func(7);

n8taOP•3y ago

Testing My case is actually A->B and B->B so I need to adapt it slightly Okay able to run yours as is. thanks you! Working on modifying now @thinker227 any idea what I might being doing wrong here?

            Expression<Func<List<int>, int>> a = x => x[0];
            Expression<Func<int, int>> b = x => x * 2;

            var param = Expression.Parameter(typeof(int), "x");
            var listParam = Expression.Parameter(typeof(List<int>), "x");
            
            var c = Expression.Lambda<Func<List<int>, int>>(
                Expression.Invoke(a, Expression.Invoke(b, listParam)), param);

            var func = c.Compile();
            int i = func(new List<int>() {5,6,7});
            Console.WriteLine(i);

            Expression<Func<List<int>, int>> a = x => x[0];
            Expression<Func<int, int>> b = x => x * 2;

            var param = Expression.Parameter(typeof(int), "x");
            var listParam = Expression.Parameter(typeof(List<int>), "x");
            
            var c = Expression.Lambda<Func<List<int>, int>>(
                Expression.Invoke(a, Expression.Invoke(b, listParam)), param);

            var func = c.Compile();
            int i = func(new List<int>() {5,6,7});
            Console.WriteLine(i);

System.ArgumentException: Expression of type 'System.Collections.Generic.List`1[System.Int32]' cannot be used for parameter of type 'System.Int32'

Thinker•3y ago

I think you only need one param The lambda you're expecting is a Func<List<int>, int> so you can't pass in a parameter of type int Replace param with listParam and it should work™️

n8taOP•3y ago

Isn't the param when you call b different ? Since B accepts an int vs A accepting a List<int>

Thinker•3y ago

oh, yeah Right you have to do it in the reverse order, swap a and b

n8taOP•3y ago

Okay sec testing Got it You are right we only need one param

            Expression<Func<List<int>, int>> a = x => x[0];
            Expression<Func<int, int>> b = x => x * 2;

            var param = Expression.Parameter(typeof(int), "x");
            var listParam = Expression.Parameter(typeof(List<int>), "x");

            var interMediate = Expression.Invoke(a, listParam);
            
            var c = Expression.Lambda<Func<List<int>, int>>(Expression.Invoke(b, interMediate), listParam);

            var func = c.Compile();
            int i = func(new List<int>() {5,6,7});
            Console.WriteLine(i);

            Expression<Func<List<int>, int>> a = x => x[0];
            Expression<Func<int, int>> b = x => x * 2;

            var param = Expression.Parameter(typeof(int), "x");
            var listParam = Expression.Parameter(typeof(List<int>), "x");

            var interMediate = Expression.Invoke(a, listParam);
            
            var c = Expression.Lambda<Func<List<int>, int>>(Expression.Invoke(b, interMediate), listParam);

            var func = c.Compile();
            int i = func(new List<int>() {5,6,7});
            Console.WriteLine(i);

$ 10 Thank you for the help! Now I just gotta convert this to my real types haha should be ez

Accord•3y ago

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Combine two Expression Func [Answered]