C#•3y ago

Combining func reference behavior [Answered]

If i combine func3 += func1 and func3 += func2 and then lets say func1 += someMethod Will func3 also have it added?

10 Replies

mtreit•3y ago

Well, not directly But indirectly yes Like if you removed func1 from the chain subsequently then invoking func3 will not result in a call to someMethod

Xan.NavaOP•3y ago

Exactly what I was hoping for Though if you did func3 -= someMethod would it be removed from func1 also?

333fred•3y ago

Xan.NavaOP•3y ago

Is it is more like sets. The func3 set has two sets in it func1 and func2, and then func1 is a set with someMethod in it? So removing someMethod from func3 wouldn't work because it's set is just func1 and func2 but calling func3 will call everything in its sub sets?

MODiX•3y ago

Orannis#3333

REPL Result: Success

var func1 = () => Console.WriteLine("Func1");
var func2 = () => Console.WriteLine("Func2");
var func3 = () => Console.WriteLine("Func3");
var combined1and2 = func1 + func2;
var combinedAll3 = func3 + combined1and2;
combined1and2 -= func2;
combinedAll3();

var func1 = () => Console.WriteLine("Func1");
var func2 = () => Console.WriteLine("Func2");
var func3 = () => Console.WriteLine("Func3");
var combined1and2 = func1 + func2;
var combinedAll3 = func3 + combined1and2;
combined1and2 -= func2;
combinedAll3();

Console Output

Func3
Func1
Func2

Func3
Func1
Func2

Compile: 629.132ms | Execution: 69.840ms | React with ❌ to remove this embed.

mtreit•3y ago

Yes, think of it as a graph

333fred•3y ago

See how modifying combined1and2 didn't affect combinedAll3?

Xan.NavaOP•3y ago

ah yeah

333fred•3y ago

I'm going to assume this is done

Accord•3y ago

✅ This post has been marked as answered!

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Combining func reference behavior [Answered]